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The sequence {a}_{1}, {a}_{2}, ..., {a}_{n}, ... is such that {a}_{n}=4a_{n-1}-{3} for all integers n > 1. If {a}_{3}={x}, then {a}_{1} =
  • A4x – 3
  • B16x – 15
  • C\frac{x+3}{4}
  • D\frac{x+3}{16}
  • E\frac{x+15}{16}
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正确答案: E

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Jillian

Jillian

a3 = 4a2 -3 = 4(4a1-3)-3 = 16a1-15 = x

=> a1 = (x+15)/16

2012-09-22 17:42:05  IP属地:保留地址

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